X^2+4X-22/3X+10/3X+16/9X=-4

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Solution for X^2+4X-22/3X+10/3X+16/9X=-4 equation: 


X in (-oo:+oo)

X^2+4*X-((22/3)*X)+(10/3)*X+(16/9)*X = -4 // + 4

X^2+4*X-((22/3)*X)+(10/3)*X+(16/9)*X+4 = 0

X^2+4*X+(-22/3)*X+(10/3)*X+(16/9)*X+4 = 0

X^2+16/9*X+4 = 0

DELTA = (16/9)^2-(1*4*4)

DELTA = -1040/81

DELTA < 0

X belongs to the empty set

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